mampir,sekalian bikin Q.;-;

[tex] {9}^{0} + {1}^{999} \times {2}^{12} = ....[/tex]

btw, yotsuba wangy:v​

mampir,sekalian bikin Q.;-;

[tex] {9}^{0} + {1}^{999} \times {2}^{12} = ....[/tex]

btw, yotsuba wangy:v​

Hasil Dari Operasi tersebut adalah 4.097

_____________

[tex] \sf = {9}^{0} + {1}^{999} \times {2}^{12} [/tex]

[tex] \sf = 1 + 1 \times {2}^{12} [/tex]

[tex] \sf = 1 + (2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times \times 2 \times 2 \times 2 \times 2)[/tex]

[tex] = 1 + (4 \times 4 \times 4 \times 4 \times4 \times 4)[/tex]

[tex] = 1 + (16 \times 16 \times 16)[/tex]

[tex] = 1 + 4.096[/tex]

[tex] = 4.097[/tex]

_______

nt:

perkalian didahulukan

a^0 = 1

aⁿ = a × a × a × a... (n faktor)

1ⁿ = 1

______________

ありがとう!

Jawaban:

4.097

Penjelasan dengan langkah-langkah:

[tex] {9}^{0} + {1}^{999} \times {2}^{12} [/tex]

[tex] = (9 \div 9) + (1 \times (2 \times 2 \times ...2))[/tex]

[tex] = 1 + (1 \times 4.096)[/tex]

[tex] = 1 + 4.096[/tex]

[tex] = 4.097[/tex]

[tex]\boxed{\tt \: Answer \: By:\color{FF66B2}{♡}\color{FF6666}{m}\color{FFB266}{e}\color{B2FF66}{l}\color{66FF66}{v}\color{66FFFF}{i}\color{66B2FF}{a}\color{6666FF}{a}\color{B266FF}{y}\color{FF66FF}{u}\color{FF66B2}{6}\color{FF9999}{6}\color{FFCC99}{9}\color{FF66B2}{♡}}[/tex]

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